2x^2+x+8=x^2-5

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Solution for 2x^2+x+8=x^2-5 equation: 



2x^2+x+8=x^2-5

We move all terms to the left:

2x^2+x+8-(x^2-5)=0

We get rid of parentheses

2x^2-x^2+x+5+8=0

We add all the numbers together, and all the variables

x^2+x+13=0

a = 1; b = 1; c = +13;
Δ = b2-4ac
Δ = 12-4·1·13
Δ = -51
Delta is less than zero, so there is no solution for the equation

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